小程序开发定制C++上机题汇总

C++小程序开发定制期末复习题目汇总

小程序开发定制本人汇总了本学期上机考的题目，小程序开发定制并借鉴和自己编写了这些代码。

///题目如下

1.小程序开发定制字母大小写转换

#include<iostream>using namespace std;void change(char x) {	x += 32;	cout << x << endl;}int main() {	char a;	cin >> a;	change(a);	return 0;}
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2.小程序开发定制计算圆的周长和面积

#include<iostream>using namespace std;#define PI 3.14class Circle{public:	Circle(double radius) {		this->C = 2 * PI * radius;		this->S = PI * radius * radius;		cout << this->C << " " << this->S << endl;	}	double S;	double C;};int main() {	double radius;	cin >> radius;	Circle a(radius);	return 0;}
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3.小程序开发定制数据逆序输出

#include<iostream>using namespace std;int function(int n) {	int temp = 0;	while (n > 0) {		n /= 10;		temp++;	}	return temp;}int main() {	int array[10];	int num, x;	cin >> num;	x = function(num);	for (int i = 0; i < x; i++) {		array[i] = num % 10;		num /= 10;	}	for (int i = 0; i < x; i++) {		cout << array[i];	}	return 0;}
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4.小程序开发定制判断是否是闰年

#include<iostream>using namespace std;void function(int a ){	if (a % 4 == 0 && a % 100 != 0 || a % 400 == 0) {		cout << "是" << endl;	}	else {		cout << "不是" << endl;	}}int main() {	int year;	cin >> year;	function(year);	return 0;}
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5.小程序开发定制打点滴实验

#include<iostream>using namespace std;void calculate(int V){	int num = 1, time = 2, sum = 0;	while (V-num > 0) {		V -= num;		num++;		sum += time;		time++;	}	if (V > 0) {		sum += V;	}	cout << sum << endl;}int main(){	int V;	cin >> V;	calculate(V);	return 0;}
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6.小程序开发定制母牛生小牛,小程序开发定制四年生一头

#include<iostream>using namespace std;int func(int N){	if (N < 4)	{		return 1;	}	else	{		return func(N - 1) + func(N - 3);	}}int main(){	int N;	cin >> N;	cout << func(N);	return 0;}
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7.输出1-100（每行十个），并输出序号为素数的元素（一行十个）

代码一：

#include<iostream>using namespace std;int main() {	int arr[100];	for (int i = 0; i < 100; i++)	{		arr[i] = i+1;	}	for (int i = 0; i <100; i+=10)	{		for (int j = 0; j < 9; j++)		{			cout << arr[i + j]<<" ";		}		cout << arr[i + 9] << endl;	}//寻找100以内素数	int arr1[50];	int temp = 0, count = 0;	for (int i = 2; i <= 100; i++)	{		for (int j = 2; j < i; j++)		{			if (i % j == 0)			{				temp = 1;				break;			}		}		if (temp == 0)		{			count++;			arr1[count-1] = i;		}		temp = 0;	}		cout << arr[arr1[0]] << " ";	for (int i = 1; i<count; i++)	{		if (i % 10 != 9) 		{			cout << arr[arr1[i]] << " ";		}		else		{			cout << arr[arr1[i]] << endl;		}	}	return 0;}
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代码二：

#include<iostream>using namespace std;int main(){	int a[100];	int n = 1;	for (int i = 0; i < 100; i++)	{		a[i] = n;		n++;	}	for (int i = 0; i < 100; )	{		for (int j = 0; j < 9; j++)		{			cout << a[i] << " ";			i++;		}		cout << a[i++] << endl;	}	int m = 1;	cout << 3 << " ";	for (int i = 3; i < 100; i++)	{		int sum = 0;		for (int j = 2; j < i / 2 + 1; j++)		{			int x;			x = i % j;			if (x == 0)				sum++;		}		if (sum == 0)		{			m++;			if (m < 10)				cout << a[i] << " ";			else if (m >= 10)			{				m = 0;				cout << a[i] << endl;			}		}	}	return 0;}
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8.仓库结算
某仓库共有ABCDE五种货物，每天需要补货的数量不同，每种货物的单价不同，如下所示。由键盘输入五种货物需要补货的数量，请计算出当日仓库需支付多少货款。
货物名称 货物单价
A 10
B 5
C 3
D 20
E 13

#include<iostream>using namespace std;int main(){	int m, sum = 0;	char P;	for (int i = 0; i < 5; i++)	{		cin >> P >> m;		switch (P)		{		case'A':			sum += 10 * m;			break;		case'B':			sum += 5 * m;			break;		case'C':			sum += 3 * m;			break;		case'D':			sum += 20 * m;			break;		case'E':			sum += 13 * m;			break;		}	}	cout << sum << endl;	return 0;}
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9.编写一个评分统计程序。从键盘获取8个评委打分的百分制成绩（double类型），统计平均分时，去掉一个最高分和一个最低分其余6个分数的平均值即为最后得分。请将这个分数输出到屏幕上，格式为：平均成绩是XXX。

#include<iostream>using namespace std;void func(double arr[]){	int num = 7, num1;	double sum = 0;	while (num)	{		num1 = num;		num = 0;		for (int i = 0; i < num1; i++)		{			if (arr[i]<arr[i+1])			{				double temp = arr[i];				arr[i] = arr[i + 1];				arr[i + 1] = temp;				num = i;			}		}	}	for (int i = 1; i < 7; i++)	{		sum += arr[i];	}	cout <<"平均成绩是"<< sum / 6 << endl;}int main(){	double score[8];	for (int i = 0; i < 8; i++) 	{		cin >> score[i];	}	func(score);	return 0;}
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10.编写一个记录5个学生的姓名、性别、年龄和学号的程序，要求使用结构数组表示学生信息，用for循环获得键盘输入的学生记录的数据，所有数据输入完毕后，将5个学生的信息在屏幕上输出，格式要求：按表格行列格式输出，每行输出一个学生的信息，按照姓名、性别、年龄、学号的顺序，各列信息左对齐，各信息占10位。

#include<iostream>#include<iomanip>#include<string>using namespace std;struct Student{	string name;	string sex;	int age;	string number;};Student P[5];int main(){	for (int i = 0; i < 5; i++)	{		cin >> P[i].name >> P[i].sex >> P[i].age >> P[i].number;	}	for (int i = 0; i < 5; i++)	{		cout << setiosflags(ios::left)			<< setw(10) << P[i].name			<< setw(10) << P[i].sex			<< setw(10) << P[i].age			<< setw(10) << P[i].number << endl;	}	return 0;}
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11.定义一个结构型变量（包括年、月、日），并从键盘上获取该变量的值，计算该日在本年中是第几天，输出到屏幕上，格式为：“X年X月X日是本年中的第X天。”（提示：注意闰年问题）。

代码一：

#include<iostream>using namespace std;class Date{	friend void func(Date *p);public:	Date(int y, int m, int d)	{		this->year = y;		this->month = m;		this->day = d;	}	int year;	int month;	int day;};int judgement(int y){	if (y % 400 == 0 || y % 4 == 0 && y % 100 != 0) {		return 1;	}	else {		return 0;	}}void func(Date &p){	int arr[12];	int sum = 0;	if (judgement(p.year)) 	{		arr[1] = 29;	}	else {		arr[1] = 28;	}	arr[0] = arr[2] = arr[4] = arr[6] = arr[7] = arr[9] = arr[11] = 31;	arr[3] = arr[5] = arr[8] = arr[10] = 30;	for (int i = 0; i < p.month - 1; i++)	{		sum += arr[i];	}	sum += p.day;	cout << p.year << "年" << p.month << "月" << p.day << "日是本年中的第" << sum << "天" << endl;}int main(){	int y, m, d;	cin >> y >> m >> d;	Date a(y, m, d);	func(a);	return 0;}
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代码二：

#include<iostream>using namespace std;struct Date{	int year;	int month;	int day;};bool judge(int y){	int sum = 0;	if (y % 100 == 0)	{		if (y % 400 == 0)return true;		else return false;	}	else {		if (y % 4 == 0)return true;		else return false;	}}int main(){	Date d;	cin >> d.year >> d.month >> d.day;	int a[12];	if (judge(d.year))	{		a[1] = 29;	}	else	{		a[1] = 28;	}	a[0] = a[2] = a[4] = a[6] = a[7] = a[9] = a[11] = 31;	a[3] = a[5] = a[8] = a[10] = 30;	int sum = 0;	for (int i = 0; i < d.month - 1; i++)	{		sum += a[i];	}	sum += d.day;	cout << d.year << "年" << d.month << "月" << d.day << "日是本年中的第" << sum << "天" << endl;	return 0;}
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12.从键盘输入一行或几行字符串，行数由键盘输入，一行字符串用字符数组存储。请统计所输入的字符串中26个字母（不区分大小写）出现的次数，并将出现次数非零的字母统计结果输出到屏幕上，格式参见样例。如果没有字母，请输出字符串中无字母。

代码一：

#include<iostream>using namespace std;int main(){	const int N = 80;	char buffer[N];	int k = 0;	const int NUM = 26;	int counts[NUM] = { 0 };	char letters[NUM];	int i = 0;	int count = 0;	int num;	cin >> num;	do {		cin.getline(buffer, N, '');		k = 0;		while (buffer[k] != '\0')		{			if (tolower(buffer[k]) >= 'a' && tolower(buffer[k]) <= 'z')			{				i = tolower(buffer[k]) - 'a';				counts[i]++;			}			k++;		}		num--;	} while (num >= 0);	for (i = 0; i < NUM; i++) {		letters[i] = char('a' + i);		if (counts[i] > 0)		{			count++;			cout << letters[i] << ":" << counts[i] << endl;		}	}	if (count == 0) {		cout << "字符串中无字母。" << endl;	}}
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代码二：

#include<iostream>using namespace std;int b[26] = { 0 };void func(char a){	if (a >= 'a' && a <= 'z')	{		b[a - 'a']++;	}	else if (a >= 'A' && a <= 'Z')	{		b[a - 'A']++;	}}int main(){	int n;	cin >> n;	char a[100] = { 0 };	for (int i = 0; i < n + 1; i++)	{		cin.getline(a, 100, '');		int j = 0;		while (a[j] != '\0')		{			func(a[j]);			j++;		}	}	int count = 0;//判断有无字母	for (int i = 0; i < 26; i++)	{		if (b[i] != 0)		{			cout << char(i + 'a') << ":" << b[i] << endl;			count++;		}	}	if (count == 0)	{		cout << "字符串中无字母。" << endl;	}	return 0;}
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13.温度转换

#include<iostream>using namespace std;int main(){	double F, C;	cin >> F;	C = (F - 32) / 1.8;	cout << C << endl;	return 0;}
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14.斐波那契数列

递归版：

#include<iostream>using namespace std;int Fabo(int x){	int sum = 0;	if (x == 0)sum = 0;	else if (x == 1)sum = 1;	else sum = sum + Fabo(x - 1) + Fabo(x - 2);	return sum;}int main(){	int x;	cin >> x;	cout << Fabo(x) << endl;}
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非递归版：

#include<iostream>using namespace std;void func(int n){	if (n == 0)	{		cout << 0 << endl;	}	else if (n == 1 || n == 2) 	{		cout << 1 << endl;	}	else	{		int a = 1, b = 1, temp = 0;		for (int i = 3; i <= n; i++)		{			temp = a + b;			a = b;			b = temp;		}		cout << temp << endl;	}}int main(){	int n;	cin >> n;	func(n);	return 0;}
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15.有10个小朋友围成一圈分糖果，老师顺次分给每人一定数量糖果（初始值为偶数）然后按照下列规则调整，所有小朋友同时把自己的糖果分一半给右边的人，糖果数变为奇数的人，向老师补要一块糖果，问经过多少次调整后，大家糖果数一样多，且每人多少块。建立两个函数，一个负责传递糖果，一个负责判断所有人的糖果是否相等。

#include<iostream>using namespace std;void func(int arr[],int *arr1) {	for (int i = 1; i < 10; i++)	{		arr1[i] = arr[i] / 2 + arr[i - 1] / 2;	}	arr1[0] = arr[0] / 2 + arr[9] / 2;	for (int i = 0; i < 10; i++) 	{		if (arr1[i] % 2 != 0)		{			arr1[i]++;		}	}	for (int i = 0; i < 10; i++)	{		arr[i] = arr1[i];	}}int judgement(int arr[]){	for (int i = 0; i < 10; i++)	{		if (arr[i] != arr[0])		{			return 1;		}	}	return 0;}int main(){	int count = 0;	int arr[10] = { 0 };	int *arr1 =new int[10];	for (int i = 0; i < 10; i++)	{		cin >> arr[i];	}	while (judgement(arr))	{		func(arr,arr1);		count++;	}	cout << count <<" "<<arr[0]<< endl;	system("pause");	return 0;}
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16.歌手大奖赛共有10位评委，为每位选手打分（double型）。
预赛部分歌手的分数，为去掉1个最高分、1个最低分后其余8个分数的平均值；
决赛部分歌手的分数，为去掉2个最高分、2个最低分后其余6个分数的平均值。
通过键盘输入10位评委的打分，以及当前处于哪个阶段（预赛部分用1表示，决赛部分用2表示）。
主函数中，只负责输入数据、调用分数计算函数、输出结果，评分计算部分编写独立函数完成。

#include<iostream>using namespace std;void func(double* p){	for (int i = 0; i < 9; i++)	{		for (int j = 0; j < 9 - i; j++)		{			double temp;			temp = p[j];			p[j] = p[j + 1];			p[j + 1] = temp;		}	}}double js(double* p){	double sum = 0;	for (int i = 2; i < 8; i++)	{		sum += p[i];	}	return sum / 6.0;}double ys(double* p){	double sum = 0;	for (int i = 1; i < 9; i++)	{		sum += p[i];	}	return sum / 8.0;}int main() {	double* p = new double[10];	for (int i = 0; i < 10; i++)	{		cin >> p[i];	}	int x;	cin >> x;	if (x == 1) {		cout << ys(p) << endl;	}	if (x == 2) {		cout << js(p) << endl;	}	delete[]p;	return 0;}
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17.编写一个函数get_average()获取整型数组元素的平均值。
要求这个函数既可以用来求一维数组元素的平均值，
也可以求二维数组元素的平均值。
在main()函数中通过具体的一维数组Array_1D和二维数组Array_2D测试这个函数。
假定一维数组为a[5],二维数组为b[2][3],一维数组和二维数组的变量值由键盘分别输入，
在屏幕上输出一维数组和二维数组的平均值，平均值间用一个空格分开。

#include<iostream>using namespace std;int main(){		double sum1 = 0, sum2 = 0;	int a[5];	int b[2][3];	for (int i = 0; i < 5; i++)	{		cin >> a[i];		sum1 += a[i];	}	for (int i = 0; i < 2; i++)	{		for (int j = 0; j < 3; j++)		{			cin >> b[i][j];			sum2 += b[i][j];		}	}	cout << sum1 / 5 << " " << sum2 / 6 << endl;	return 0;}
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18.编制程序，调用指针作为参数的函数，实现下面两字符串变量的交换。 char* ap=“hello”; char* bp=“how are you”;
交换的结果为：ap 指向"how are you"，bp 指向"hello"。 (注意：输出语句中的;和.为英文符号)

#include<iostream>using namespace std;void swap(char* a, char* b){	char* t;	t = a;	a = b;	b = t;}int main(){	const char* ap = "hello.";	const char* bp = "how are you;";	swap(ap, bp);	cout << "ap指向" << ap << endl;	cout << "bp指向" << bp << endl;	return 0;}
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19.用字符指针数组，将给定的5个字符串（可以是任意5个国家名字）进行排序并输出。

#include <iostream>using namespace std;int main() {	char* name[5];	char arr[5][100];	for (int i = 0; i < 5; i++)	{		cin >> arr[i];	}	for (int i = 0; i < 5; i++)	{		name[i] = arr[i];	}	for (int i = 0; i < 5; i++)	{		for (int j = 0; j < 4 - i; j++)		{			if (*name[j]>*name[j+1]) 			{				char* t = name[j];				name[j] = name[j + 1];				name[j + 1] = t;			}		}	}	for (int i = 0; i < 5; i++)	{		cout << name[i] << endl;	}	return 0;}
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20.已知有3名学生及五门课程的成绩，要求根据学生的各科平均分排序（降序）,并输出学生的所有信息和平均分（用指针数组完成）。

#include <iostream>using namespace std;struct student {	char name[10];	int score[5];	float aver;};student a[3];int main() {	for (int i = 0; i < 3; i++)	{		cin >> a[i].name;		float num = 0;		for (int j = 0; j < 5; j++) 		{			cin >> a[i].score[j];			num += (float)a[i].score[j];		}		a[i].aver = num / 5;	}	student* p[3];	for (int i = 0; i < 3; i++)	{		p[i] = &a[i];	}	for (int i = 0; i < 2; i++)	{		for (int j = 0; j < 2 - i; j++)		{			if (p[j]->aver < p[j + 1]->aver) {				student* temp;				temp = p[j];				p[j] = p[j + 1];				p[j + 1] = temp;			}		}	}	for (int i = 0; i < 3; i++) 	{		cout << p[i]->name << " ";		for (int j = 0; j < 5; j++)		{			cout << p[i]->score[j] << " ";		}		cout << p[i]->aver << endl;	}	return 0;}
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21.请编写函数实现将一个数值插入到数组中适当的位置，使新数组按降序排列，并将插入的位置输出到屏幕上。 说明：1）原数组大小和数值由键盘输入，动态创建数组； 2）插入的数值由键盘输入。
3)如果插入数据与原数组中某数据相同，则插在该数据之前。

#include<iostream>using namespace std;int main(){	int num,num1;	cin >> num;	int* p = new int[100];	int* x = new int[100];	for (int i = 0; i < num; i++)	{		cin >> p[i];	}	for (int i = 0; i < num - 1; i++)	{		for (int j = 0; j < num - i - 1; j++)		{			if (p[j] < p[j + 1])			{				int temp = p[j];				p[j] = p[j + 1];				p[j + 1] = temp;			}		}	}	cin >> num1;	x[0] = num1;	for (int i = 0; i < num; i++)	{		x[i + 1] = p[i];	}	int count = 1;	for (int i = 0; i < num ; i++)	{		if (x[i] < x[i + 1])		{			int temp = x[i];			x[i] = x[i + 1];			x[i + 1] = temp;			count++;		}	}	cout << count << endl;	system("pause");	return 0;}
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22.老王的密码

#include<iostream>using namespace std;int main(){	int num = 0;	char* p = new char[100];	cin >> p;	for (int i = 0; i < 100; i++)	{		if (p[i] == NULL) {			num = i;			break;		}	}	for (int i = 0; i < num; i++) {		if (p[i] >= 'a' && p[i] <= 'z') 		{			if (p[i] >= 'a' && p[i] <= 'c')			{				p[i] = '2';			}			else if(p[i] >= 'd' && p[i] <= 'f')			{				p[i] = '3';			}			else if (p[i] >= 'g' && p[i] <= 'i')			{				p[i] = '4';			}			else if (p[i] >= 'j' && p[i] <= 'l')			{				p[i] = '5';			}			else if (p[i] >= 'm' && p[i] <= 'o')			{				p[i] = '6';			}			else if (p[i] >= 'p' && p[i] <= 's')			{				p[i] = '7';			}			else if (p[i] >= 't' && p[i] <= 'v')			{				p[i] = '8';			}			else			{				p[i] = '9';			}		}		else if (p[i] >= 'A' && p[i] <= 'Z') {			p[i] = p[i] + 33;		}		else		{			p[i] = p[i];		}	}	for (int i = 0; i < num; i++) {		cout << p[i];	}			  	system("pause");	return 0;}
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23.矩形类

#include<iostream>using namespace std;class Rec {public:	Rec(double R_len,double R_wid) {		this->R_len = R_len;		this->R_wid = R_wid;		this->S = this->R_len * this->R_wid;	}	double R_len;	double R_wid;	double S;	Rec compare(Rec rec1, Rec rec2);};Rec Rec::compare(Rec rec1, Rec rec2) {	if (rec1.S > rec2.S) {		return rec1;	}	else {		return rec2;	}}int main() {	double l, w;	cin >> l >> w;	Rec rec1(5.2,4.3);	Rec rec2(100,20);	Rec rec3(l, w);	cout <<(rec1.compare(rec1.compare(rec1,rec2),rec3)).S << endl;	system("pause");	return 0;}
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24.三角类

#include<iostream>using namespace std;class Tri {public:	Tri(int a, int b, int c) {		this->L1 = a;		this->L2 = b;		this->L3 = c;	}	int L1;	int L2;	int L3;	void judgement(int a1, int a2, int a3);};void Tri::judgement(int a1,int a2,int a3) {	if ((a1 + a2 > a3) && (a1 + a3 > a2) && (a2 + a3 > a1)) {		if (a1 == a2 && a2== a3) {			cout << "A equileteral triangle" << endl;		}		else if ((a1 == a2)  | (a1 == a3) | (a2 == a3) ) {			cout << "A isosceles triangle" << endl;		}		else if ((a1 * a1 == a2 * a2 + a3 * a3) || (a2 * a2 == a1 * a1 + a3 * a3) || (a3 * a3 == a2 * a2 + a1 * a1)) {			cout << "A right triangle" << endl;		}		else {			cout << "A triangle" << endl;		}	}	else {		cout << "Not a triangle" << endl;	}}int main() {	int a, b, c;	cin >> a >> b >> c;	Tri S(a, b, c);	S.judgement(S.L1, S.L2, S.L3);	system("pause");	return 0;}
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25.时间类

#include<iostream>using namespace std;class Time {public:	Time(int a, int b, int c);	void func(bool d);	int Year;	int Month;	int Day;};Time::Time(int a, int b, int c) {	this->Year = a;	this->Month = b;	this->Day = c;}void Time::func(bool d) {	if (d == true) {		cout << Year << "-" << Month << "-" << Day << endl;	}	else {		cout << Year << "年" << Month << "月" << Day << "日" << endl;	}}int main() {	char str[15];	int a, b, c, i;	bool e;	cin >> a >> b >> c>> str;		for (i = 0; str[i]; i++)		{			if (str[i] == '.')				break;		}		if (str[i])			e = false;		else			e = true;	Time T(a, b, c);	T.func(e);	system("pause");	return 0;}
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26.员工薪金管理类

#include<iostream>#include<string>using namespace std;class employee{public:	int num;	string name;	int money;	int year;	int month;	int day;	employee(int a, std::string b, int c, int d, int e, int f)	{		this->num = a;		this->name = b;		this->money = c;		this->year = d;		this->month = e;		this->day = f;	}	int sum(int x, int y);};int employee::sum(int x, int y){	int time = (x - year) * 12 + y - month;	int sum = time * money;	return sum;}int main(){	employee a(1, "wang", 5000, 2000, 10, 23);	employee b(2, "liu", 4500, 2008, 1, 20);	employee c(3, "huo", 3800, 2003, 7, 3);	employee d(4, "ma", 5300, 2015, 4, 10);	employee e(5, "meng", 6000, 2016, 3, 16);	int x, y, z;	cin >> x >> y >> z;	switch (x) {	case 1:		cout << a.name << " " << a.sum(y, z) << endl;		break;	case 2:		cout << b.name << " " << b.sum(y, z) << endl;		break;	case 3:		cout << c.name << " " << c.sum(y, z) << endl;		break;	case 4:		cout << d.name << " " << d.sum(y, z) << endl;		break;	case 5:		cout << e.name << " " << e.sum(y, z) << endl;		break;	}	return 0;}
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以上就是一些题目，不敢保证代码写的很完美，仅供参考。